Mov ax word ptr sp
Nettetmov AX, WORD PTR B mov BH, BYTE PTR A. Stack. Hardware Stack ; SP register ; points to top of stack ; push reg/mem; SP := SP - 2 ; copy Operand to SP ; pop … Nettet8. feb. 2013 · mov bx,word ptr [b+1] which has effect of copying a word at address b+1 into bx. Now dd instructs to allocate a dword and assign 256 to it. 256 in hex is represented as 00000100h. The dword will be allocated in memory like this 00010000h - bytes 00h, 01h, 00h, 00h because on x86 lower bytes are stored at lower addresses (so-called …
Mov ax word ptr sp
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NettetMOV AL,BYTE PTR DA_WORD SUB DA_BYTE,AL A. 0EAH B. 0FAH C. 0F5 D. 00H 5. 设数据段中已有: DA1 DB 12H,34H DA2 DW 56H,78H 下面有语法错误的语句是( )。 A. MOV DA1+2,AX B. ADR DW DA1 C. MOV BYTE PTR DA2+1,AL D. MOV WORD PTR DA1+1,AX View Code 6. … Nettetcall word ptr内存单元地址word = 字(16位) 相当于push ip jmp word ptr内存单元地址. mov sp,10h. mov ax,0123h. mov ds:[0],ax. call word ptr ds:[0] 执行后(ip)=0123H (sp)=0EH. call dword ptr内存单元地址dword双字(32位) 返回指令ret和retf. call和ret和retf配合使用 例:计算2的n次方,计算前n的值由cx提供。
Nettet28. okt. 2024 · 微机原理第三章习题与参考答案.pdf,第三章习题与参考答案 3.1 已知 (ds) = 1000h ,(es) = 2000h ,(ss) = 3000h ,(si) = 0050h , (bx) =0100h ,(bp) =0200h , 数据变量 disp 的偏移地址为 1000 。指出下列指令的寻址方式和物理地址。 (1) mov ax,0abh 立即寻址 无 (2) mov ax,bx 寄存器寻址 无 (3) mov ax,[l0 00h] 直接寻址 10000h (4) mov ... Nettetmov AX, WORD PTR B mov BH, BYTE PTR A. Stack. Hardware Stack ; SP register ; points to top of stack ; push reg/mem; SP := SP - 2 ; copy Operand to SP ; pop reg/mem; TOS copied to Operand ; SP := SP + 2 ; push AX pop AX push Num pop Num.STACK 100h. Stack size specified in Bytes ; 100h ; Items pushed and popped as words ; 100h …
Nettet31. aug. 2024 · jmp word ptr 内存单元地址 比如,下面的指令: mov sp,10h mov ax,0123h mov ds: [0],ax call word ptr ds: [0] 执行后, (IP)=0123H, (sp)=0EH。 (2)call dword ptr 内存单元地址 用汇编语法来解释此种格式的call指令,则: CPU执行“call dword ptr 内存单元地址”时,相当于进行: push CS push IP jmp dword ptr 内存单 … Nettet11. mar. 2024 · mov ax,WORD PTR variable is loading the first 2 bytes of the variable, not the whole variable. If you want to store the first 2 bytes of eax, you have to use ax as the source operand. Thus you'd use mov WORD PTR variable, ax.The word ptr has to go on the memory operand, and it has to match the register. It's only needed at all because …
Nettet30. jan. 2010 · mov ax,[bx]这样就可以了,第一个操作数已经表明了操作的类型是字大小的数据了。 必须显示声明操作数据大小的一般第一个操作数是内存单元的,比如 mov …
Nettet30. apr. 2024 · I don't understand the difference between MOV and MOV ptr. For example, in this C code: unsigned char x, y; x = 2; the second line in assembly is: `MOV x, 2`. but the second line of this C code : tabbyte [0] = 15 unsigned char tabbyte [4] in assembly is : MOV byte ptr tabbyte [0], 15. chip media player downloadNettet我们可以通过下列代码来检查这些标志:mov eax, fs:[30h]mov eax, [eax+68h]and eax, 0x70test eax, eaxjne @DebuggerDetected在上面的代码中,我们还是访问PEB,然后通过将PEB的地址加上偏移量68h到达堆操作例程所使用的这些标志的起始位置,通过检查这些标志就能知道是否存在调试器。 chip mediatek dimensity 920 5ghttp://www.masmforum.com/board/index.php?topic=17817.0;prev_next=prev grants for law school studentsNettet微机原理及应用复习题. 1. 执行下面的程序段后,CX的内容是 ( ). 2. 执行下面的程序段后,AX的内容是 ( ), BX的内容是. ( ). 1、下面的程序段是统计AX中16位二进制数1的个数,并将结果放在CX中,填空使程序完成预定的功能。. 1. 所有PC机具有相同的机器指令。. grants for learning disabled studentsNettet12. des. 2013 · MOV [BX], 100这条指令,数据的类型不确定。. 汇编程序不知道你这条指令是字节操作还是字操作。. 如果你后面的源操作数不是100,而是大于255的某个数,有一部分汇编程序可以通过,因为超过255的数一定不会是字节数,一定是字操作数。. 给存储器赋 … chip mediathek downloadNettet4. mar. 2024 · 设X、Y、Z、W均为双字长数据,各自的低十六位数和高十六位数分别存放在X、X+2、Y、Y+2、Z、Z+2的存储单元中,结果的低十六位字和高十六位字分别存放 … grants for law enforcement 2023Nettet5. des. 2016 · (1)mov ah,cx 类型不匹配或两操作数字长不相等 (2)mov 33h,al 立即数不能做目的操作数 (3)mov ax,[si][di] 两变址寄存器不能同时使用 (4)mov [bx],[si] 两操作数不能同时为存储器操作数 (5)add byte ptr[bp],256 两操作数类型不匹配 (6)mov data[si],es:ax 源操作数形式错,寄存器操作数不加段重设 ... chip mediatek helio g85